Question

A student has 23mL of a 1.2M solution of acid. He adds water until he has 50.0mL of the solution. What is his new concentration?

Answer 1

To solve this problem, we can use the formula:

C1V1 = C2V2

where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.

We are given:

C1 = 1.2 M
V1 = 23 mL
V2 = 50.0 mL

We can solve for C2 by plugging in the values:

C1V1 = C2V2

(1.2 M)(23 mL) = C2(50.0 mL)

C2 = (1.2 M)(23 mL) / (50.0 mL)

C2 = 0.552 M

Therefore, the new concentration of the solution is 0.552 M.