0.375 g of a monoprotic acid (mm = 245 g/mol) is dissolved in water to produce 25.0 mL of a solution with pH = 3.28. Determine the ionization constant of the acid.

Question

asked Aug 27, 2024 131k views

1 Answer

← Prev Question Next Question →

Ask a Question

Nerdybeardo · Answer 1 · 2024-09-03T09:58:40+0000

Answer: 4.5 × 10^-6.

Explanation: 0.375 grams of a monoprotic acid is dissolved in water to produce 25.0 milliliters of a solution with pH = 3.28. this would give you 4.5 times 10 to the power of negative six.

0.375 g of a monoprotic acid (mm = 245 g/mol) is dissolved in water to produce 25.0 mL of a solution with pH = 3.28. Determine the ionization constant of the acid.

0 Comments

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

0 Comments

Please log in or register to add a comment.

Related questions

Other Questions