Question

A car is traveling at 40 m/s and the 90 Kg driver slams on the brakes to

avoid a collision. If the car slows down to a velocity of 5 m/s and the
acceleration occurred in 3 seconds, how much force did the seatbelt
apply to the driver?

Answer 1

Step-by-step explanation:

F = ma

m = 90 kg

a = change in v / change in time = (40-5)m/s / 3 s = 11.67 m/s^2

F = ma = 90 kg ( 11.67 m/s^2 ) = 1050 N