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A line passes through the points (5, 1.5) and (1, 2.5).
Create an equation of the line.

User Eli Sadoff
by
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1 Answer

4 votes

Hello !

Answer:


\boxed{\sf y=-0.25x+2.75}

Explanation:

A line passes through two points :

  • (5, 1.5)
  • (1, 2.5)

Moreover, the slope-intercept form of a line is of the form
y=mx+b.

We want to find the coefficients m and b.

Let's replace x and y with 5 and 1.5, and then with 1 and 2.5.


\begin{cases}1.5=5m+b \\2.5=m+b\end{cases}

We get a system of two equations to solve.

Let's subtract the second line from the first one :


1.5-2.5=5m+b-(m+b)\\\iff -1=4m\\\iff \boxed{m=-(1)/(4)=-0.25}

Let's substitute
-0.25 for m in the second equation :


2.5=-0.25 +b\\\iff \boxed{b=2.75}

An equation of the line is
y=-0.25x+2.75.

Have a nice day ;)

User Dale
by
8.6k points

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