Answer:
the plane 2.2 miles away from the runway
Step-by-step explanation:
Given the data in the question and as illustrated in the image below;
from the image, using trigonometric ratio;
SOH CAH TOA
sin = opposite / hypotenuse
sin10° = 0.38 / x
xsin10° = 0.38
x = 0.38 / sin10°
x = 0.38 / 0.173648
x = 2.1883 miles ≈ 2.2 miles { the nearest tenth of a mile }
Therefore, the plane 2.2 miles away from the runway