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Margo is wrapping a box that is 7 inches long, 10 inches wide, and 4 inches high. How much wrapping paper will she need to cover the entire box?

User Shereen
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2 Answers

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Answer:280 in

Step-by-step explanation: First we multiply the length by the width and that would be 7 by 10 and we would get 70. Next we multiply the height by the total of (l x w), so 4 x 70 would be 280. Margo needs a total of 280 inches of wrapping paper to cover the entire box. Hope this helps! :)

User Nick Ball
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She will need to cover a total of 268 square inches of wrapping paper.

She will need to cover six sides of the box. To calculate the surface area of the box, you'll need to add the area of each side. The formula for surface area is: 2lw + 2lh + 2wh. Plugging in the dimensions of the box, we get:

2(7 x 10) + 2(7 x 4) + 2(10 x 4) = 140 + 56 + 80 = 276

So, she will need 276 square inches of wrapping paper. But since she doesn't need to wrap the bottom of the box, we subtract one of the sides, which gives us a total of 268 square inches of wrapping paper.

To calculate the surface area of the box, you need to add the area of all six sides. The area of each side can be found by multiplying the length by the width.

- The area of the front and back sides is 7 x 4 = 28 square inches each.
- The area of the top and bottom sides is 10 x 4 = 40 square inches each.
- The area of the two side sides is 7 x 10 = 70 square inches each.

So, the total surface area of the box is 2(28) + 2(40) + 2(70) = 56 + 80 + 140 = 276 square inches.

Therefore, Margo will need at least 276 square inches of wrapping paper to cover the entire box.
User Gauri Bhosle
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