Answer:
$10 and the cost of a dessert is $5.
Explanation:
Let’s solve this problem using a system of linear equations. Let’s say the cost of a burger meal is x and the cost of a dessert is y. From the information given, we can write two equations:
John: 6x + 2y = 70 Sandy: 9x + 8y = 130
Multiplying the first equation by 4, we get:
24x + 8y = 280
Subtracting the second equation from this, we get:
24x + 8y - (9x + 8y) = 280 - 130 15x = 150 x = 10
Substituting this value of x in the first equation, we get:
6 * 10 + 2y = 70 60 + 2y = 70 2y = 10 y = 5
So the cost of a burger meal is $10 and the cost of a dessert is $5.