Answer:
- boat: 30 mph
- current: 10 mph
Explanation:
Given that a 440 mi trip downriver took 11 hours, and the return trip took 22 hours, you want to know the speeds of the boat and current.
Sum
The trip downriver was at a speed of ...
speed = distance/time = 440 mi/(11 h) = 40 mi/h
Difference
The trip upriver was at a speed of ...
distance/time = 440 mi/(22 h) = 20 mi/h
Boat speed
The boat's speed is half the sum of these speeds:
(b + c) +(b -c) = 2b = (40 +20) mi/h
b = 30 mi/h
Current speed
The current's speed is the difference:
(b +c) = 40
c = 40 -b = 40 -30
c = 10 . . . mi/h
The speed of the boat in still water is 30 mi/h; the speed of the current is 10 mi/h.
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Additional comment
We essentially wrote two equations:
using b = boat speed and c = current speed.
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