Answer:
the solution points for the system of equations are (3, 25) and (-7/2, -7).
Explanation:
We can solve this system of equations using substitution or elimination. Here, we will use the substitution method:
Substitute y = 2x^2 + 5x - 10 into the second equation:
4x - (2x^2 + 5x - 10) = -11
Simplifying the left side of the equation:
4x - 2x^2 - 5x + 10 = -11
Rearranging the terms:
2x^2 - x + 21 = 0
Using the quadratic formula:
x = (-(-1) ± sqrt((-1)^2 - 4(2)(21))) / 2(2)
x = (1 ± sqrt(169)) / 4
x = (1 ± 13) / 4
Simplifying:
x = 3 or x = -7/2
Now, substitute each value of x back into one of the original equations to find the corresponding value(s) of y:
For x = 3:
y = 2(3)^2 + 5(3) - 10 = 25
So one solution point is (3, 25).
For x = -7/2:
y = 4(-7/2) + 11 = -7
So the other solution point is (-7/2, -7).
Therefore, the solution points for the system of equations are (3, 25) and (-7/2, -7).