a) To find the volume of one block of gold, we use the formula for the volume of a right trapezoidal prism:
V = (1/2)h(b1+b2)L
where h is the height of the trapezoid, b1 and b2 are the lengths of the two parallel sides of the trapezoid, and L is the lateral edge of the prism. Substituting the given values, we get:
V = (1/2)(8)(10+7)(19) = 6844 cubic inches
Therefore, the total volume of 10 blocks of gold is:
10 x 6844 = 68440 cubic inches
b) To find the weight of the gold, we first convert the volume from cubic inches to cubic feet:
68440/1728 = 39.583 cubic feet
Next, we convert the volume to pounds:
39.583 x 1206.83 = 47800.5 pounds
Finally, we convert the weight to troy pounds:
47800.5/0.82 = 58292.07 troy pounds
The value of the gold is:
58292.07 x $13,067.76 = $760,834,385.79
Therefore, the total worth of Otto's gold based on the given information is approximately $760,834,385.79.