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How many µg of mercury are contained in 27.2 mL of a 14.10 ppm solution?

1 Answer

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To calculate the amount of mercury in µg (micrograms), we need to use the following formula:

mass (in µg) = volume (in mL) x concentration (in ppm) x atomic mass (in g/mol) / 1000

The atomic mass of mercury (Hg) is 200.59 g/mol.

Substituting the given values into the formula, we get:

mass = 27.2 mL x 14.10 ppm x 200.59 g/mol / 1000

mass = 76.9 µg

Therefore, there are 76.9 µg of mercury in 27.2 mL of a 14.10 ppm solution.
User RawMean
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