What is the probability that a randomly selected personal checking account will have a daily balance of less than $750?
To answer this question, we need to calculate the z-score for a daily balance of $750 using the mean and standard deviation provided:
z = (x - μ) / σ = (750 - 900) / 175 = -0.857
Using a standard normal distribution table or calculator, we can find the probability that a z-score is less than -0.857:
P(z < -0.857) = 0.1952
Therefore, the probability that a randomly selected personal checking account will have a daily balance of less than $750 is approximately 0.1952 or 19.52%.