Question

Beyond struggling pls help
FIND THE FOLLOWING MEASUREMENTS

Answer 1

angle CED 90°. CE = 21. EB = 8.

Explanation:

angle CED = 90° (right angle).

the radius (centre to edge) is the same right around the circle.

so that means that distance CD = 29.

draw a line from C to D. notice how that has just become an hypotenuse?

we know that DE = 20.

we have a right-angled triangle.

CE² = hypot² - DE²

= 29² - 20²

= 841 - 400

= 441

CE = √441 = 21.

EB must be radius subtract CE. that is, 29 - 21 = 8.

Answer 2

Check the picture below.

well, ∡CED is the same as ∡CEA and those are right-angles so those are pretty much given, now

`\begin{array}{llll} \textit{using the pythagorean theorem} \\\\ a^2+o^2=c^2\implies o=√(c^2 - a^2) \end{array} \qquad \begin{cases} c=\stackrel{hypotenuse}{29}\\ a=\stackrel{adjacent}{20}\\ o=\stackrel{opposite}{CE} \end{cases} \\\\\\ CE=√( 29^2 - 20^2)\implies CE=√( 841 - 400 ) \implies CE=√( 441 )\implies \boxed{CE=21} \\\\\\ \stackrel{\textit{since we know the radius CB=29}}{CB-CE = EB\implies }\boxed{EB=8}`