Question

PLEASE HELP FAST! Find the equation of a line that bisects the line segment joining the points (-1,3) and (5,-3) and intersects the x-axis at the origin.

Answer 1

Answer: y=0

Explanation:

Mid point of line segment joining (a,b) and (p,q) =
`((a+p)/(2),(b+q)/(2))`

Mid point of line segment joining the points (-1,3) and (5,-3) =
`((-1+5)/(2),(3-3)/(2))`

`=(\frac42,\frac02)\\= (2,0)`

Equation of line passing through (a,b) and (c,d) is given by :-

`(y-b)=(d-b)/(c-a)(x-a)`

Equation of line passing through (2,0) and (0,0) will be:

`(y-0)=(0-0)/(2-0)(x-0)\\\\\\ y=0`