Question

(c) Write
3"
9-1
as a power of 3

Answer 1

Let's first start by rewriting the denominator to have a base of 3.

9 = 3^2

9^(n - 1) = 3^2(n - 1)

Now that we have two terms with the same base, we can subtract the exponents.

3^n / 3^2(n - 1) = 3^[n - 2(n - 1)]

3^[n - 2n + 2]

3^[-n + 2]

3^-(n - 2)

Answer: 3^(-n + 2) OR 3^-(n - 2)

Hope this helps!