52.4k views
5 votes
How would you write the following expression as a sum or difference?

How would you write the following expression as a sum or difference?-example-1

1 Answer

5 votes

Answer:

B: 1/3 log (2-x) - log 3x

Explanation:

some log laws:

1) log xy = log x + log y

2) log (x/y) = log x - log y

3) log x^k = k log x

log ((∛2-x) / 3x)

= log ∛2-x - log 3x (just like the 2nd law above)

log ∛2-x = log (2-x)^(1/3) = (1/3) log (2-x) (just like the 3rd law above).

so we now have (1/3) log (2 - x) - log 3x

This is option B in the question.

User Reddyvaribabu
by
8.2k points

No related questions found