Answer:
B: 1/3 log (2-x) - log 3x
Explanation:
some log laws:
1) log xy = log x + log y
2) log (x/y) = log x - log y
3) log x^k = k log x
log ((∛2-x) / 3x)
= log ∛2-x - log 3x (just like the 2nd law above)
log ∛2-x = log (2-x)^(1/3) = (1/3) log (2-x) (just like the 3rd law above).
so we now have (1/3) log (2 - x) - log 3x
This is option B in the question.