Answer:
Step-by-step explanation:
Here's the answer.
To calculate the maximum possible speed of the toy car when it reaches position B, we can use the principle of conservation of energy, which states that the total energy of a closed system remains constant. In this case, the closed system is the toy car, and the initial potential energy at position A is converted into kinetic energy at position B.
The potential energy of the car at position A is given by:
PE_A = mgh
Where:
m is the mass of the car, which is 0.040 kg
g is the gravitational field strength, which is 9.8 N/kg
h is the vertical height between position A and position B, which is 90 cm or 0.9 m
PE_A = 0.040 kg x 9.8 N/kg x 0.9 m
PE_A = 0.3528 J
At position B, the potential energy of the car is zero, and all of the initial potential energy has been converted into kinetic energy. The kinetic energy of the car at position B is given by:
KE_B = 1/2 mv^2
Where:
v is the speed of the car at position B
We can set the potential energy at A equal to the kinetic energy at B and solve for v:
PE_A = KE_B
0.3528 J = 1/2 x 0.040 kg x v^2
v^2 = 8.82 m^2/s^2
Taking the square root of both sides, we get:
v = sqrt(8.82 m^2/s^2)
v = 2.97 m/s
Therefore, the maximum possible speed of the toy car when it reaches position B is approximately 2.97 m/s.