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The total mass of a trolley and some watermelons is 27 kg.

The total mass of the same trolley and some mangoes is 11 kg.
The mass of the watermelons was thrice the mass of the mangoes.

User Jokober
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1 Answer

1 vote

Answer:

Therefore, the mass of the trolley (T) and the mass of the watermelons (W) cannot be determined uniquely based on the given information. We can only express their relationship using Equation (3): 3T + W = 33.

Explanation:

Let's assign variables to the masses involved to solve the problem systematically.

Let's say:

Mass of the trolley = T kg

Mass of the mangoes = M kg

Mass of the watermelons = W kg

According to the given information:

The total mass of the trolley and mangoes is 11 kg:

T + M = 11 -- Equation (1)

The mass of the watermelons is three times the mass of the mangoes:

W = 3M -- Equation (2)

Now, we can use these equations to find the values of T, M, and W.

From Equation (2), we can express M in terms of W:

M = W / 3

Substitute this value of M into Equation (1):

T + W / 3 = 11

Multiply through by 3 to eliminate the fraction:

3T + W = 33 -- Equation (3)

Now, we have a system of two equations (Equation 2 and Equation 3) with two unknowns (T and W). We can solve this system to find the values.

Since we don't have a specific value for any variable, we can express the solution in terms of the variables.

Therefore, the mass of the trolley (T) and the mass of the watermelons (W) cannot be determined uniquely based on the given information. We can only express their relationship using Equation (3): 3T + W = 33.

User Slacktracer
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8.2k points