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1 vote
I need help with this and if you are able to find the answer pls show the steps thank you ​

I need help with this and if you are able to find the answer pls show the steps thank-example-1

1 Answer

3 votes

Answer:

c. 34.5 m

Explanation:

Over horizontal ground, the range R for velocity v and launch angle θ is:

R=v^2sin2θ/g

=35^2sin16∘/9.8

= 34.5 meters (so the answer is (c))

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