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What volume would 1.72 x 1023 molecules of an ideal gas occupy at STP?

User Cae Vecchi
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Answer:

6.70 liters of volume

Step-by-step explanation:

At STP (Standard Temperature and Pressure), the temperature is 273.15 K (0°C) and the pressure is 1 atm (101.325 kPa).

To determine the volume of the gas, we can use the ideal gas law, which relates the pressure, volume, temperature, and number of molecules of a gas:

PV = nRT

where:

P = pressure (in atm)

V = volume (in liters)

n = number of moles of gas

R = gas constant (0.08206 L·atm/K·mol)

T = temperature (in Kelvin)

To solve for the volume, we can rearrange the equation:

V = (nRT)/P

We are given the number of molecules of the gas, which is 1.72 x 10^23. To convert this to moles, we need to divide by Avogadro's number:

n = (1.72 x 10^23)/(6.022 x 10^23) = 0.286 moles

Substituting the values into the equation, we get:

V = (0.286 mol x 0.08206 L·atm/K·mol x 273.15 K)/1 atm = 6.70 liters

Therefore, 1.72 x 10^23 molecules of an ideal gas would occupy 6.70 liters of volume at STP.

User Stanleyli
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