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Solve the system of equations:

3x-8y+z=8
-x+y-z = -1
x-3y = 3
X=
Y=
Z=

1 Answer

2 votes

Step 1: Add Equation 2 and Equation 3 to eliminate z.

(-x + y - z) + (x - 3y) = -1 + 3

y - 4y = 2

-3y = 2

y = -2/3

Step 2: Substitute the value of y (-2/3) into Equation 3 to find the value of x.

x - 3(-2/3) = 3

x + 2 = 3

x = 1

Step 3: Substitute the values of x and y into Equation 1 to find the value of z.

3(1) - 8(-2/3) + z = 8

3 + 16/3 + z = 8

9/3 + 16/3 + z = 8

25/3 + z = 8

z = 8 - 25/3

z = 24/3 - 25/3

z = -1/3

Therefore, the solution to the system of equations is:

x = 1

y = -2/3

z = -1/3

User LiamRyan
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