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(2x+5)a + (x+3)b = 2x+4 calcule (a-b)^2

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Answer:

Explanation:

Let's first expand the left side of the given equation:

(2x+5)a + (x+3)b = 2x+4

2xa + 5a + xb + 3b = 2x + 4

Now, let's group the terms with x and the terms without x:

(2a + b)x + (5a + 3b) = 2x + 4

We can see that the coefficients of x are equal on both sides, so we can equate the coefficients of x and the constant terms separately:

2a + b = 2 (1)

5a + 3b = 4 (2)

Solving these two equations, we get:

a = 2/7

b = 8/7

Now, we can substitute these values of a and b into the expression (a-b)^2 and simplify:

(a-b)^2 = (2/7 - 8/7)^2

= (-6/7)^2

= 36/49

Therefore, the value of (a-b)^2 is 36/49.

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