Answer:Before the collision, the truck had no kinetic energy since it was at rest. The car also had no kinetic energy since it was stationary. Therefore, the initial kinetic energy of the system was zero.
After the collision, the truck and car move with a common speed of 2 m/s. The total mass of the system is:
m = mass of truck + mass of car
m = 8,800 kg + 1,000 kg
m = 9,800 kg
The final kinetic energy of the system is:
KE_final = (1/2) * m * v^2
KE_final = (1/2) * 9,800 kg * (2 m/s)^2
KE_final = 19,600 J
The amount of kinetic energy "lost" in the collision is therefore:
KE_lost = KE_initial - KE_final
KE_lost = 0 J - 19,600 J
KE_lost = -19,600 J
The negative sign indicates that kinetic energy was not conserved in the inelastic collision, and that some of the initial kinetic energy was lost due to deformation and other forms of energy dissipation.
Step-by-step explanation:
Before the collision, the truck had no kinetic energy since it was at rest. The car also had no kinetic energy since it was stationary. Therefore, the initial kinetic energy of the system was zero.
After the collision, the truck and car move with a common speed of 2 m/s. The total mass of the system is:
m = mass of truck + mass of car
m = 8,800 kg + 1,000 kg
m = 9,800 kg
The final kinetic energy of the system is:
KE_final = (1/2) * m * v^2
KE_final = (1/2) * 9,800 kg * (2 m/s)^2
KE_final = 19,600 J
The amount of kinetic energy "lost" in the collision is therefore:
KE_lost = KE_initial - KE_final
KE_lost = 0 J - 19,600 J
KE_lost = -19,600 J
The negative sign indicates that kinetic energy was not conserved in the inelastic collision, and that some of the initial kinetic energy was lost due to deformation and other forms of energy dissipation.