Question

5) If Oskar bisects the diameter of a circle, what is he trying to construct?

6) What is the center and radius of a circle with the equation (x - 5)+ (y + 3)2 = 49

Answer 1

Center = (5,-3) and radius = 7

Explanation:

(5) If Oskar bisects the diameter of a circle, what is he trying to construct the radius of the circle.

(6) The given equation is :

`(x-5)^2+(y+3)^2=49`

The general equation of circle is given by :

`(x-a)^2+(y-b)^2=r^2` ...(1)

Where

(a,b) are the coordinates of the centre and r is the radius.

The given equation can be written as :

`(x-5)^2+(y+3)^2=7^2` ..(2)

Comparing equation (1) and (2) we get :

a = 5, b = -3 and r = 7

So,

Center = (5,-3) and radius = 7

Hence, this is the required solution.