Question

Help please!! this is due tonight and I have no clue what I'm doing

Answer 1

Explanation:

{3, 4, 7, 9, 12, 18, 31}

Question #1: 1/3f = 4

1/3(3) = 1

1/3(4) = 4/3

1/3(7) = 7/3

1/3(9) = 3

1/3(12) = 4

1/3(18) = 6

1/3(31) = 31/3

Question #2: 1/3f < 4

True = 3, 4, 7, 9

False = 12, 18, 31

Question #3: m + 7 = 20

3 + 7 = 10

4 + 7 = 11

7 + 7 = 14

9 + 7 = 16

12 + 7 = 19

18 + 7 = 25

31 + 7 = 38

none of the numbers in the set make the equation true.

Question #4: m + 7
`\geq` 20

False = 3, 4, 7, 9, 12

True = 18 and 31

Answer 2

1. 12 2. 3, 4, 7, and 9. 3. 18 and 32

Explanation:

To find number 1, you have to find what multiplied by 1/3 is 4. In other words, what divided by 3 is 4. That is 12, so the first is 12, and it can't be anything else. For number 2, you can just put anything less than 12, because 4 would be greater. So, it's 3, 4, 7, and 9. For number 3, you have to imagine what plus 7 is 20, it's 13, but it's not there, so there's nothing for number 3. For number 4, you can put any numbers 13 and greater, because it's a greater or equal sign. So, it's 18 and 32.