Answer:
Let me explain
Step-by-step explanation:
The balanced equation for the given reaction is:
3Cu + 8NO3- + 4H+ → 3Cu2+ + 2NO + 4H2O
Here's how to balance the equation using the half-reaction method:
Half-reaction for oxidation: Cu → Cu2+
To balance this half-reaction, we need to add two electrons to the left side:
Cu → Cu2+ + 2e-
Half-reaction for reduction: NO3- → NO
To balance this half-reaction, we need to add three electrons to the right side:
NO3- + 3e- → NO
Now, we need to balance the number of electrons in both half-reactions. To do this, we need to multiply the oxidation half-reaction by three and the reduction half-reaction by two:
3Cu → 3Cu2+ + 6e-
2NO3- + 6e- → 2NO
Now, we can combine the two half-reactions by adding them together and canceling out the electrons:
3Cu + 8NO3- + 4H+ → 3Cu2+ + 2NO + 4H2O
This is the balanced equation for the given reaction.