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Balance using half rxn meathod: Cu + NO3- -> Cu2+ + NO

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Answer:

Let me explain

Step-by-step explanation:

The balanced equation for the given reaction is:

3Cu + 8NO3- + 4H+ → 3Cu2+ + 2NO + 4H2O

Here's how to balance the equation using the half-reaction method:

Half-reaction for oxidation: Cu → Cu2+

To balance this half-reaction, we need to add two electrons to the left side:

Cu → Cu2+ + 2e-

Half-reaction for reduction: NO3- → NO

To balance this half-reaction, we need to add three electrons to the right side:

NO3- + 3e- → NO

Now, we need to balance the number of electrons in both half-reactions. To do this, we need to multiply the oxidation half-reaction by three and the reduction half-reaction by two:

3Cu → 3Cu2+ + 6e-

2NO3- + 6e- → 2NO

Now, we can combine the two half-reactions by adding them together and canceling out the electrons:

3Cu + 8NO3- + 4H+ → 3Cu2+ + 2NO + 4H2O

This is the balanced equation for the given reaction.

User Harshvardhan Joshi
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