Answer:
The correct answer is option B: 47.11°.
Step-by-step explanation:
To calculate the angle of refraction when light passes from air to water, we can use Snell's law, which states:
n₁ * sin(θ₁) = n₂ * sin(θ₂)
where:
n₁ = refractive index of the medium of incidence (in this case, air) = 1.0
n₂ = refractive index of the medium of refraction (in this case, water) = 1.33
θ₁ = angle of incidence
θ₂ = angle of refraction (what we want to find)
Given:
θ₁ = 77º
Let's plug in the values into Snell's law and solve for θ₂:
1.0 * sin(77º) = 1.33 * sin(θ₂)
sin(77º) = (1.33 * sin(θ₂)) / 1.0
Now, isolate sin(θ₂) by multiplying both sides by 1.0:
sin(77º) * 1.0 = 1.33 * sin(θ₂)
sin(θ₂) = (sin(77º) * 1.0) / 1.33
Now, take the inverse sine (arcsin) of both sides to find θ₂:
θ₂ = arcsin((sin(77º) * 1.0) / 1.33)
Calculating the value:
θ₂ ≈ 47.11º
Therefore, the angle of refraction in the water when the angle of incidence is 77º is approximately 47.11º.