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Sam theows a ball up into the air and watches it come down. The equation for the height, h, in relation to time,t , is h=5f^2+25t. What is the range for height of the ball

User Truemedia
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1 Answer

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Answer:

h = 5t²+ 25t

from projectiles

h = u²sin²∆ / 2g

taking the angle to be ∆

and range is u²sin2∆/g

Therefore integrate the equation h= 5t²+25t

R = 5t³/3 + 25t²/2 + t

User Srinivasan Sekar
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