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3 votes
Which equation has infinitely many solutions?

O 2(3x - 10) = 6x + 20 Jhry
O 16 + 3x
-
3x + 16
O 4x10-2(-2x + 5)
O-7x +9 = 9x - 7

Which equation has infinitely many solutions? O 2(3x - 10) = 6x + 20 Jhry O 16 + 3x-example-1

2 Answers

3 votes

Answer: 4x - 10 = -2(-2x + 5)

Explanation:

An equation has an infinitely many solutions when both sides are equal to each other.

-2(-2x+5) expands to become (-2*-2)*x + 5*(-2) = 4x - 10

Since the other side of the equation is also 4x - 10, both sides of the equation are identical and thus the equation has infinitely many solutions.

User Sem Vanmeenen
by
8.6k points
2 votes

Answer:

it's is D

This is because equation 1 to 3 results in only a constant but D x will be 1

User Artem Tokmakov
by
8.7k points