Question

2y+3/3y-8=3/2
find the value of y

Answer 1

2y+3/3y-8=3/2

multiply through by 3

3(2y+3-8)= (3/2)*3

6y-5= 9/2

6y =9/2+5

6y=19/2

y= 19*6/2

y= 57

Answer 2

y=6

Explanation:

Multiply both sides by 3y-8.

2y+3=9y/2-12

Add 12 to both sides.

2y+15=9y/2

Multiply both sides by 2.

Subtract both sides by 4y.

30=5y

Divide both sides by 5.

Therefore, y=6.