Solve for n. n/n_1 +2/n+1 =2

asked May 11, 2024 154k views

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Answer:

Explanation:

$(n)/(n-1)+(2)/(n+1) = 2\\(n^2+n + 2n-2)/(n^2-1) = 2\\ n^2+3n-2 = 2n^2-2\\n^2=3n\\n^2-3n= 0\\n(n-3) = 0\\n = 0 \\or\\ n = 3$

Noobar answered May 16, 2024

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