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16 G of oxygen at 15° above 18 how many liters of oxygen is in a container

User Manur
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Answer:

To determine the volume of 16 g of oxygen at 15°C and 1 atm pressure, we can use the ideal gas law equation:

PV = nRT

Where P is the pressure in atm, V is the volume in liters, n is the number of moles, R is the gas constant (0.0821 L atm/mol K), and T is the temperature in Kelvin.

First, we need to convert the temperature from Celsius to Kelvin:

T = 15°C + 273.15 = 288.15 K

Next, we need to calculate the number of moles of oxygen:

n = m/M

Where m is the mass of oxygen (16 g) and M is the molar mass of oxygen (32 g/mol).

n = 16 g / 32 g/mol = 0.5 mol

Now we can rearrange the ideal gas law equation to solve for V:

V = nRT/P

V = (0.5 mol)(0.0821 L atm/mol K)(288.15 K) / 1 atm = 11.3 L

Therefore, there are 11.3 liters of oxygen in the container.

Step-by-step explanation:

User Steve Potter
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