Answer:
To determine the volume of 16 g of oxygen at 15°C and 1 atm pressure, we can use the ideal gas law equation:
PV = nRT
Where P is the pressure in atm, V is the volume in liters, n is the number of moles, R is the gas constant (0.0821 L atm/mol K), and T is the temperature in Kelvin.
First, we need to convert the temperature from Celsius to Kelvin:
T = 15°C + 273.15 = 288.15 K
Next, we need to calculate the number of moles of oxygen:
n = m/M
Where m is the mass of oxygen (16 g) and M is the molar mass of oxygen (32 g/mol).
n = 16 g / 32 g/mol = 0.5 mol
Now we can rearrange the ideal gas law equation to solve for V:
V = nRT/P
V = (0.5 mol)(0.0821 L atm/mol K)(288.15 K) / 1 atm = 11.3 L
Therefore, there are 11.3 liters of oxygen in the container.
Step-by-step explanation: