Answer:
The compound which would not yield 2-propanone when treated with H2O/H3O is 2-methylpropane.
2-propanone is a ketone, which means that it has a carbonyl group (C=O) attached to a carbon atom that is also attached to two hydrogen atoms. 2-methylpropane, on the other hand, is an alkane, which means that it has only single bonds between its carbon atoms. When 2-propanone is treated with H2O/H3O, the carbonyl group is hydrolyzed to form 2-propanol. However, when 2-methylpropane is treated with H2O/H3O, no reaction occurs because there is no carbonyl group to be hydrolyzed.
Here are the chemical equations for the reactions of 2-propanone and 2-methylpropane with H2O/H3O:
2-propanone
CH3COCH3 + H2O/H3O -> CH3CH2CH2OH
2-methylpropane
CH3CH(CH3)2 + H2O/H3O -> no reaction
Step-by-step explanation: