205k views
2 votes
The attraction force between two particles is inversely proportional to the square of the distance between them. If the force is F when the distance between them is 2r and the force is kF when the distance is 3r, find the value of k. ​

The attraction force between two particles is inversely proportional to the square-example-1

1 Answer

5 votes
Let's denote the force between the two particles as F and the distance between them as d. We know that the force is inversely proportional to the square of the distance, which can be expressed as:

F ∝ 1/d^2

Using proportionality, we can write:

F = k/d^2

where k is a constant of proportionality.

If the distance between the particles is 2r, then we have:

F = k/(2r)^2 = k/4r^2

If the distance between the particles is 3r, then we have:

kF = k/d^2 = k/(3r)^2 = k/9r^2

We can then set these two expressions equal to each other and solve for k:

k/4r^2 = k/9r^2

Multiplying both sides by 36r^2 (the least common multiple of 4r^2 and 9r^2), we get:

9k = 4k

Simplifying, we get:

k = 4/9

Therefore, the value of k is 4/9.
User Farhan Farooqui
by
7.8k points

No related questions found