Explanation:
To determine which point is a solution of the linear inequality 92 + 3y < 6, we can substitute the values of each point into the inequality and check if the inequality holds true.
Let's evaluate the inequality for each point:
1. Point (1, -1):
92 + 3(-1) < 6
92 - 3 < 6
89 < 6
The inequality is not true for this point.
2. Point (2, -2):
92 + 3(-2) < 6
92 - 6 < 6
86 < 6
The inequality is not true for this point.
3. Point (1, 1):
92 + 3(1) < 6
92 + 3 < 6
95 < 6
The inequality is not true for this point.
4. Point (1, 3):
92 + 3(3) < 6
92 + 9 < 6
101 < 6
The inequality is not true for this point.
None of the given points satisfy the inequality. Therefore, none of the points (1, -1), (2, -2), (1, 1), or (1, 3) are solutions to the linear inequality 92 + 3y < 6.