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a cool water sample absorbed 3135 j of energy from hot metal. the temperature of the 63 g piece of metal changed from c to 20 c what is the specific heat of the metal

2 Answers

3 votes

Answer: 156.75 J/C

Step-by-step explanation:

Q=CT (C is specific heat and T is change in temperature)

Disclaimer: I am assuming the initial temperature is 0 degrees Celsius because the question has been worded improperly. This assumption is not made because it is true, but because there is not enough information in the current question to solve for the specific heat. Also, the mass of the sample is given, which is unnecessary for solving the specific heat but necessary to solve for the specific heat capacity. Either the question has not been worded properly or the mass given is just to trick students.

Rearrange to isolate C: C = Q/T

Solve for C: C = 3135/(20-0) = 3135/20 = 156.75 J/C

User BenMorganIO
by
7.4k points
4 votes

Answer: 0.137

Step-by-step explanation:

acellus

User Jakraska
by
8.1k points