Answer:
sin²θ
Explanation:
* trig identities are sin²θ + cos²θ = 1, sin²θ = 1 - cos²θ.
tan²θ = sin²θ/cos²θ.
sec²θ = 1/cos²θ.
Now we can begin to work it out.
(sec²θ - 1) / (1 + tan²θ)
Simplify sec and tan
((1/cos²θ) - 1) / (1 + (sin²θ/cos²θ))
now multiply every term by cos²θ
((cos²θ/cos²θ) - cos²θ) / ((cos²θ + sin²θ))
= (1 - cos²θ) / 1
= 1 - cos²θ
= sin²θ