Question

Brandon had 40% more balls than Cody. Brandon gave 30% of his balls to Cody. Cody in return gave 50% of his balls to Brandon. Within the conclusion, Cody had 852 less balls than Brandon. How numerous balls did Brandon have at to begin with?

Answer 1

Let B be the number of balls Brandon had initially, and C be the number of balls Cody had initially.

We know that Brandon had 40% more balls than Cody, so:

B = 1.4C

We also know that Brandon gave 30% of his balls to Cody, so Cody received:

0.3B

And we know that Cody gave 50% of his balls to Brandon, so Brandon received:

0.5(0.3B) = 0.15B

Now, we can set up an equation to represent the final number of balls Cody had:

C + 0.3B - 0.5(0.3B) = C - 0.15B

And we know from the problem that Cody had 852 less balls than Brandon in the end, so:

C - 0.15B = B - 852

We can substitute B = 1.4C into this equation to get:

C - 0.15(1.4C) = 1.4C - 852

Simplifying this equation, we get:

0.79C = 852

Solving for C, we get:

C = 1078

And since B = 1.4C, we have:

B = 1.4(1078) = 1511.2

So Brandon initially had 1511 balls. However, since we're dealing with whole numbers of balls, we need to round to the nearest integer. Therefore, the final answer is:

Brandon initially had 1511 balls

Explanation:

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