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If a stone falls from rest at the top of a mineshaft to the bottom in 6 seconds, then the depth of the shaft is about

a.180 m.
b.360 m
c.60 m.
d.36 m.

User Yennefer
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1 Answer

2 votes

Answer:

180 m

Step-by-step explanation:


s=u\, t+\frac 12 \,g\,t^2 = 0\cdot 6 +\frac 12\cdot 10 \cdot 6^2 = 180

User MathGladiator
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