Question

At the freezing point of water (0∘C), Kw=1.2×10−15. Calculate [H+] and [OH−] for a neutral solution at this temperature. [H+], [OH−] = ??

Answer 1

At the freezing point of water (0°C) with a Kw of 1.2 × 10^-15, the concentrations of [H+] and [OH-] in a neutral solution are both equal to 1.1 × 10^-8.5 M.

Step-by-step explanation:

The ion-product constant for water (Kw) at the freezing point (0°C) is 1.2 × 10-15. In a neutral solution, the concentrations of hydrogen ion ([H+]) and hydroxide ion ([OH-]) are equal. To calculate their concentrations, we can take the square root of Kw. So, [H+] = [OH-] = 1.1 × 10-8.5 M.