Answer:
Abelito had the greater average speed
Explanation:
Given
Bobby:


Abelito


Required:
Who had a greater average speed
Average speed (S) is calculated as:

We will make use of mph (miles per hour) as the unit of speed.
For Bobby:

Convert minute to hour


For Abelito

Convert minute to hour


By comparison: 12.5mph > 8mph
Hence: Abelito had the greater average speed