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What is the poh of an aqueous solution at 25.0 °c that contains 3.98 ⋅ 10-9 m hydroxide ion?

User Kaosad
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1 Answer

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Final answer:

The pOH of an aqueous solution with a hydroxide ion concentration of 3.98 × 10^-9 M at 25 °C, use the formula pOH = -log[OH-]. The calculated pOH is approximately 8.4, indicating a basic solution.

Step-by-step explanation:

The POH of a solution can be calculated using the concentration of hydroxide ions (OH-) present in the solution. At 25 °C, the relationship between pOH and hydroxide ion concentration is given by the formula: pOH = -log[OH-].

Given the hydroxide ion concentration is 3.98 × 10-9 M, we can calculate the pOH:

pOH = -log(3.98 × 10-9)

Using a calculator, we find:

pOH ≈ 8.4

Furthermore, since we know that at 25 °C, the sum of pH and pOH is always equal to 14.00 (14.00 = pH + pOH), we can infer that a higher pOH corresponds to a more basic solution and a lower pOH to a more acidic solution.

User Gunnerone
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