Question

Write an equation of the line that passes through a pair of points:

(-4,-3), (-3,1)
a. y = 4x-13
b. y=-4x + 13
d.
y = 4x + 13
y = 4x -
13

Answer 1

`(\stackrel{x_1}{-4}~,~\stackrel{y_1}{-3})\qquad (\stackrel{x_2}{-3}~,~\stackrel{y_2}{1}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{1}-\stackrel{y1}{(-3)}}}{\underset{\textit{\large run}} {\underset{x_2}{-3}-\underset{x_1}{(-4)}}} \implies \cfrac{1 +3}{-3 +4} \implies \cfrac{ 4 }{ 1 } \implies 4`

`\begin{array}ll \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{ 4}(x-\stackrel{x_1}{(-4)}) \implies y +3 = 4 ( x +4) \\\\\\ y+3=4x+16\implies {\Large \begin{array}{llll} y=4x+13 \end{array}}`