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A merry-go-round has a radius of 10 ft. To the nearest tenth of a foot, what distance does

the merry-go-round cover when it rotates through an angle of 72°?

User Compito
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1 Answer

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The distance covered by the merry-go-round when it rotates through an angle of 72° is equal to the arc length of the corresponding sector of the circle with radius 10 ft and central angle 72°.

The formula for arc length is:

Arc length = (central angle / 360°) x 2πr

where r is the radius of the circle.

Substituting the given values, we get:

Arc length = (72° / 360°) x 2π(10 ft)
= 0.2 x 20π
= 4π ft
≈ 12.6 ft (rounded to the nearest tenth)

Therefore, the distance covered by the merry-go-round is approximately 12.6 feet.
User TomKraljevic
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