Answer:
A) r = -2sin(θ)
B) r = 8
Explanation:
You want the polar coordinate versions of these Cartesian equations:
Conversion
The conversion between Cartesian coordinates and polar coordinates can be accomplished using the relations ...
A)
Substituting for x and y, we have ...
(r·cos(θ))² +(r·sin(θ))² = -2r·sin(θ)
Dividing by r and using the Pythagorean identity, we have ...
r = -2·sin(θ)
B)
Substituting for x and y, we have ...
(r·cos(θ))² +(r·sin(θ))² = 64
Using the Pythagorean identity sin(θ)² +cos(θ)² = 1, this becomes ...
r² = 64
Taking the square root, we have ...
r = 8 . . . . . . the equation of a circle of radius 8.
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Additional comment
You know the Cartesian equation for a circle is ...
(x -h)² +(y -k)² = r² . . . . . . . circle of radius r centered at (h, k)
The equation of (A) can be rearranged to x² +(y +1)² = 1, by adding 2y and completing the square. This is a circle of radius 1 centered at (0, -1), as shown in the graph.
The Cartesian equation of (B) is clearly a circle centered at the origin with radius 8, as shown in the graph.
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