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17 votes
17 votes
Patrick walks 70.0 m south in 150.0 seconds. He then walks 20.0 meters north in 30.0 seconds. What is his average velocity for the trip?

0.200 m/s north
0.500 m/s south
0.278 m/s south
0.417 m/s north

User Yama
by
3.3k points

1 Answer

24 votes
24 votes

Final answer:

Patrick's average velocity for the trip is 0.278 m/s south, determined by dividing the total displacement of 50.0 m south by the total time of 180.0 seconds.

Step-by-step explanation:

To determine Patrick's average velocity for the entire trip, we need to consider the total displacement divided by the total time taken. His total displacement is the net distance covered in a particular direction. Therefore, the total displacement is 70.0 m south - 20.0 m north = 50.0 m south. The total time taken for the trip is 150.0 seconds + 30.0 seconds = 180.0 seconds.

The average velocity can be calculated by the formula:

Average velocity = Total displacement / Total time

In this case:

Average velocity = 50.0 m south / 180.0 seconds = 0.278 m/s south

Hence, the correct answer is a velocity of 0.278 m/s south.

User GTBebbo
by
2.8k points