Answer:
1.) 0.674 M
2.) 47.88 grams of CuSO4 are needed.
For the solution : first, weigh out 47.88 grams of CuSO4 using a digital balance. Secondly, add the CuSO4 to a clean and dry 250 mL volumetric flask. Next, add a small amount of distilled water to the flask and swirl to dissolve the CuSO4. After that, add more water to the flask to bring the total volume up to the 250 mL mark on the flask. Lastly, Stopper the flask and mix thoroughly by inverting several times.
The resulting solution will be 1.2 M solution of CuSO4.
3.) 217 mL is needed.
How to perform the dilution: first, measure out 217 mL of the 6.00 M sulfuric acid solution using a graduated cylinder. Then, add the measured sulfuric acid solution to a clean and dry 500 mL volumetric flask. Next, add the distilled water until the volume reaches the 500 mL mark. After that, stopper the flask and mixed thoroughly by inverting several times.
the resulting solution will be a 2.6M solution of sulfuric acid
Step-by-step explanation:
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