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suppose that water waves coming back into a dock have a velocity of 2.1 m/s and a wavelength of 5.6 m. with what frequency do these waves meet the dock

User Stolli
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In this case, the wavelength of the waves is 5.6 m, which is a relatively long wavelength. Therefore, the frequency of the waves is relatively low, at 0.38 Hz.

The frequency of a wave is defined as the number of waves that pass a given point in a given amount of time. The formula for frequency is:

f = v / λ

where:

f is the frequency in hertz (Hz)

v is the velocity of the wave in meters per second (m/s)

λ is the wavelength of the wave in meters (m)

In this case, the velocity of the waves is 2.1 m/s and the wavelength is 5.6 m. Plugging these values into the formula, we get:

f = 2.1 m/s / 5.6 m = 0.38 Hz

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Therefore, the waves meet the dock with a frequency of 0.38 Hz.

The frequency of a wave is inversely proportional to its wavelength. This means that as the wavelength increases, the frequency decreases. In this case, the wavelength of the waves is 5.6 m, which is a relatively long wavelength. Therefore, the frequency of the waves is relatively low, at 0.38 Hz.

User Smsnheck
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