Question

o−cl , s−br, c−p rank bonds from highest polarity to the lowest. to rank bonds as equivalent, overlap them.

Answer 1

The bond with the highest polarity is S-Br, followed by O-Cl, and the bond with the lowest polarity is C-P.

Step-by-step explanation:

The ranking of bonds from highest polarity to lowest polarity is as follows:

1. S-Br: The bond between sulfur and bromine has the highest polarity because bromine is more electronegative than sulfur. The electronegativity difference between the two atoms creates a larger dipole moment.
2. O-Cl: The bond between oxygen and chlorine has less polarity compared to S-Br because chlorine is less electronegative than bromine. However, it still has a significant polarity.
3. C-P: The bond between carbon and phosphorus has the lowest polarity because phosphorus is less electronegative than chlorine. The electronegativity difference between carbon and phosphorus is smaller, resulting in a weaker dipole moment.

Answer 2

To rank the bonds from highest polarity to lowest, consider the electronegativity of each atom that is bonded. The higher the electronegativity, the stronger the polarity of the bond.

Step-by-step explanation:

To rank the bonds from highest polarity to lowest, we need to consider the electronegativity of each atom that is bonded. The higher the electronegativity, the stronger the polarity of the bond. In this case, we have:

1. O-Cl (oxygen and chlorine) - Chlorine (Cl) is more electronegative than oxygen (O), so this bond has the highest polarity.
2. S-Br (sulfur and bromine) - Bromine (Br) is more electronegative than sulfur (S), so this bond has intermediate polarity.
3. C-P (carbon and phosphorus) - Phosphorus (P) is less electronegative than carbon (C), so this bond has the lowest polarity.

Therefore, the ranking from highest to lowest polarity is O-Cl, S-Br, C-P.