Question

How much heat energy is absorbed when 147 g of ice melts?

Answer in units of kJ.
also
Calculate the energy required to heat 229 g of mercury from 37 ◦C to 42 ◦C. The specific heat capacity of Hg(l) is 0.138 J/g ·◦ C.
Answer in units of cal.

Answer 1

Answer: 49.098 kJ and 37.77 cal

Step-by-step explanation:

Problem 1

Heat of fusion for water is needed since there is a phase change of water from solid to ice (Heat of fusion is 334 J/g or 0.334 kJ/g).

Q=mL (m is mass and L is latent heat, which in this case is heat of fusion)

Q = 147*0.334 = 49.098 kJ

Problem 2

1 cal = 4.184 J

Q = mcT (m is mass, c is specific heat capacity, and T is change in temperature)

Q = 229*0.138*(42-37) = 229*0.138*5 = 158.01 J

158.01 J = 37.77 cal